The explosive in a Hydrogen bomb is a mixture | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Adding the two given nuclear reactions:${ }_3 Li^6 + { }_0 n^1 \rightarrow { }_2 He^4 + { }_1 H^3$${ }_1 H^2 + { }_1 H^3 \rightarrow { }_2 He^4 +

Vedclass · Accepted Answer

$22.22$

Vedclass · Answer

(D) Adding the two given nuclear reactions:${ }_3 Li^6 + { }_0 n^1 ightarrow { }_2 He^4 + { }_1 H^3$${ }_1 H^2 + { }_1 H^3 ightarrow { }_2 He^4 + { }_0 n^1$--------------------------------------------------------------${ }_3 Li^6 + { }_1 H^2 ightarrow 2({ }_2 He^4)$---------------------------------------------------------------The energy released $(Q)$ in the process is given by $Q = \Delta m 	imes 931.5 \ MeV/amu$.$\Delta m = [M(Li^6) + M({ }_1 H^2) - 2 	imes M({ }_2 He^4)]$$\Delta m = [6.01690 + 2.01471 - 2 	imes 4.00388] \ amu$$\Delta m = [8.03161 - 8.00776] \ amu = 0.02385 \ amu$$Q = 0.02385 	imes 931.5 \ MeV \approx 22.216 \ MeV$Rounding to two decimal places,$Q = 22.22 \ MeV$.

Similar Questions

In a nuclear reactor,boron rods are used as ...... .

When Uranium is bombarded with neutrons,it undergoes fission. The fission reaction can be written as ${}_{92}U^{235} + {}_0n^1 \to {}_{56}Ba^{141} + {}_{36}Kr^{92} + 3x + Q$,where three particles named $x$ are produced and energy $Q$ is released. What is the name of the particle $x$?

Assertion : It is not possible to use ${}^{35}Cl$ as the fuel for fusion energy.
Reason : The binding energy of ${}^{35}Cl$ is too small.

In a fission reaction $_{92}^{236}U \to ^{117}X + ^{117}Y + n + n$,the binding energy per nucleon of $X$ and $Y$ is $8.5\, MeV$,whereas that of $^{236}U$ is $7.6\, MeV$. The total energy liberated will be about . . . . . . $MeV$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module