The expression left( frac{1}{sqrt{2}}hat{i} + | vedclass

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(A) Let the given vector be $\vec{P} = \frac{1}{\sqrt{2}}\hat{i} + \frac{1}{\sqrt{2}}\hat{j}$.The magnitude of a vector $\vec{A} = x\hat{i} + y\hat{j}

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Unit vector

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(A) Let the given vector be $\vec{P} = \frac{1}{\sqrt{2}}\hat{i} + \frac{1}{\sqrt{2}}\hat{j}$.The magnitude of a vector $\vec{A} = x\hat{i} + y\hat{j}$ is given by $|\vec{A}| = \sqrt{x^2 + y^2}$.Substituting the values,we get $|\vec{P}| = \sqrt{\left( \frac{1}{\sqrt{2}} \right)^2 + \left( \frac{1}{\sqrt{2}} \right)^2}$.$|\vec{P}| = \sqrt{\frac{1}{2} + \frac{1}{2}} = \sqrt{1} = 1$.Since the magnitude of the vector is $1$,it is a unit vector.

The expression $\left( \frac{1}{\sqrt{2}}\hat{i} + \frac{1}{\sqrt{2}}\hat{j} \right)$ is a

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