The far point of a myopic person is 80 , cm i | vedclass

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(A) For a myopic eye, the correcting lens is a concave lens.The far point of the myopic person is $x = 80 \, cm = 0.8 \, m$.To see distant objects (at

Vedclass · Accepted Answer

Concave lens of power $-1.25 \, D$

Vedclass · Answer

(A) For a myopic eye, the correcting lens is a concave lens.The far point of the myopic person is $x = 80 \, cm = 0.8 \, m$.To see distant objects (at infinity) clearly, the lens must form a virtual image of an object at infinity at the person's far point $(80 \, cm)$.Thus, the focal length $f$ of the corrective lens is equal to the negative of the far point distance:$f = -x = -80 \, cm = -0.8 \, m$.The power $P$ of the lens is given by the formula $P = \frac{1}{f(in \, meters)}$.$P = \frac{1}{-0.8 \, m} = -1.25 \, D$.Therefore, a concave lens of power $-1.25 \, D$ is required.

The far point of a myopic person is $80 \, cm$ in front of the eyes. What is the nature and power of the lens required to enable him to see very distant objects distinctly?

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