The final major product of the following reac | vedclass

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(B) The reaction proceeds as follows:$1$. Acetylation: $m$-toluidine reacts with $Ac_2O/Pyridine$ to form $N$-acetyl-$m$-toluidine. This protects the

Vedclass · Accepted Answer

$4-$bromo$-3-$methylaniline

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(B) The reaction proceeds as follows:$1$. Acetylation: $m$-toluidine reacts with $Ac_2O/Pyridine$ to form $N$-acetyl-$m$-toluidine. This protects the $-NH_2$ group and reduces its activating effect,preventing poly-substitution.$2$. Bromination: The acetamido group $(-NHCOCH_3)$ is ortho/para directing. Due to the steric hindrance of the $-CH_3$ group at the meta position,the bromine atom enters the para position relative to the $-NHCOCH_3$ group.$3$. Hydrolysis: The final step with $OH^-/\Delta$ removes the acetyl group to regenerate the $-NH_2$ group,yielding $4$-bromo-$3$-methylaniline.

The final major product of the following reaction is:

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Among the following,the weakest base is:

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