The first ionization potentials in electron v | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The electronic configuration of Nitrogen $(N)$ is $1s^2 2s^2 2p^3$,which has a stable half-filled $p$-orbital.The electronic configuration of Oxyg

Vedclass · Accepted Answer

$14.6, 13.6$

Vedclass · Answer

(A) The electronic configuration of Nitrogen $(N)$ is $1s^2 2s^2 2p^3$,which has a stable half-filled $p$-orbital.The electronic configuration of Oxygen $(O)$ is $1s^2 2s^2 2p^4$.Due to the extra stability of the half-filled $2p$ subshell in Nitrogen,it requires more energy to remove an electron compared to Oxygen.Therefore,the first ionization potential of Nitrogen $(14.6 \ eV)$ is higher than that of Oxygen $(13.6 \ eV)$.

The first ionization potentials in electron volts $(eV)$ of nitrogen and oxygen atoms are respectively given by:

Similar Questions

How many ionisation energies can carbon have?

$A$ neutral atom will have the lowest ionization potential when its electronic configuration is

Suppose a gaseous mixture of $He$, $Ne$, $Ar$ and $Kr$ is treated with photons of the frequency appropriate to ionize $Ar$. What ion$(s)$ will be present in the mixture?

Which of the following processes requires the largest amount of energy?

As compared to potassium,sodium has

Vedclass Test Series

Exam Paper Generator

Online Exam Module