The floor of a rectangular hall has a perimet | vedclass

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(A) Let the length,breadth,and height of the rectangular hall be $l\, m, b\, m,$ and $h\, m$ respectively.The area of the four walls is given by the f

Vedclass · Accepted Answer

$6$

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(A) Let the length,breadth,and height of the rectangular hall be $l\, m, b\, m,$ and $h\, m$ respectively.The area of the four walls is given by the formula: $	ext{Area} = 2lh + 2bh = 2(l + b)h$.The perimeter of the floor of the hall is $2(l + b) = 250\, m$.Substituting the perimeter into the area formula,we get: $	ext{Area of four walls} = 250 	imes h = 250h\, m^2$.The cost of painting is given as $Rs. 10$ per $m^2$.Total cost of painting = $	ext{Area} 	imes 	ext{Rate} = 250h 	imes 10 = 2500h$.Given that the total cost is $Rs. 15000$,we set up the equation: $2500h = 15000$.Solving for $h$: $h = \frac{15000}{2500} = 6\, m$.Therefore,the height of the hall is $6\, m$.

The floor of a rectangular hall has a perimeter of $250\, m$. If the cost of painting the four walls at the rate of $10$ per $m^2$ is $Rs. 15000$,find the height of the hall. (in $, m$)

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