The following diagram shows a Zener diode as | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: Zener voltage $V_Z = 5 	ext{ V}$, load current $I_L = 5 	ext{ mA}$.Maximum Zener current $I_Z = 4 	imes I_L = 4 	imes 5 	ext{ mA} = 20

Vedclass · Accepted Answer

$800$

Vedclass · Answer

(D) Given: Zener voltage $V_Z = 5 	ext{ V}$, load current $I_L = 5 	ext{ mA}$.Maximum Zener current $I_Z = 4 	imes I_L = 4 	imes 5 	ext{ mA} = 20 	ext{ mA}$.Total current through the series resistor $R_S$ is $I = I_L + I_Z = 5 	ext{ mA} + 20 	ext{ mA} = 25 	ext{ mA} = 25 	imes 10^{-3} 	ext{ A}$.Maximum input voltage $V_{	ext{in}} = 25 	ext{ V}$.The voltage drop across the series resistor $R_S$ is $V_{R_S} = V_{	ext{in}} - V_Z = 25 	ext{ V} - 5 	ext{ V} = 20 	ext{ V}$.Using Ohm's law, $R_S = \frac{V_{R_S}}{I} = \frac{20 	ext{ V}}{25 	imes 10^{-3} 	ext{ A}} = 800  \Omega$.

Similar Questions

The $I-V$ characteristics of an electronic device are shown in the figure. The device is:

In the following circuit,the current flowing through the $1\,k\Omega$ resistor is......$mA$.

In a Zener regulated power supply, a Zener diode with $V_z = 6 \, V$ is used for regulation. The load current is $4 \, mA$ and the unregulated input voltage is $10 \, V$. To get a Zener current five times the load current, the value of the series resistor $R_S$ is nearly:

$A$ Zener diode is connected to a battery and a load resistance as shown below. The currents $I, I_Z$ and $I_L$ respectively are:

$A$ Zener diode acts as a/an

Vedclass Test Series

Exam Paper Generator

Online Exam Module