The formula to find the mean of an ungrouped data is ........
- A$\bar{x}=\Sigma x_{i}$
- B$\bar{x}=\frac{\Sigma x_{i}}{n}$
- C$\bar{x}=\frac{\Sigma x_{i}}{2}$
- D$\bar{x}=n \cdot \Sigma x_{i}$
Explore More
Similar Questions
The mode of the following frequency distribution is $64$ and the total frequency is $200.$ Find the missing frequencies $x$ and $y.$
Class $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ $80-90$ Frequency $8$ $12$ $27$ $x$ $55$ $37$ $y$
| Class | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ | $80-90$ |
| Frequency | $8$ | $12$ | $27$ | $x$ | $55$ | $37$ | $y$ |
Medium
View SolutionIn the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$f_{0} = \ldots \ldots \ldots$
Easy
View Solution$\frac{Z-M}{M-\bar{x}}=\ldots \ldots \ldots \ldots$
Easy
View SolutionThe median class in the following frequency distribution is ..........
Class $20-25$ $25-30$ $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ Frequency $2$ $5$ $8$ $10$ $7$ $10$ $3$
| Class | $20-25$ | $25-30$ | $30-35$ | $35-40$ | $40-45$ | $45-50$ | $50-55$ |
| Frequency | $2$ | $5$ | $8$ | $10$ | $7$ | $10$ | $3$ |
Easy
View SolutionThe mean of the following frequency distribution is $60$ and the total frequency is $120$. Find the missing frequencies $f_{1}$ and $f_{2}$.
Class $10-30$ $30-50$ $50-70$ $70-90$ $90-110$ Frequency $17$ $f_{1}$ $32$ $f_{2}$ $19$
| Class | $10-30$ | $30-50$ | $50-70$ | $70-90$ | $90-110$ |
| Frequency | $17$ | $f_{1}$ | $32$ | $f_{2}$ | $19$ |
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo