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Question

(C) Given the equation $\cos(x) - \sin(x) = 0$. Rearranging the terms,we get $\cos(x) = \sin(x)$. Dividing both sides by $\cos(x)$ (assuming $\cos(x)

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$n\pi + \frac{\pi}{4}, n \in Z$

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(C) Given the equation $\cos(x) - \sin(x) = 0$. Rearranging the terms,we get $\cos(x) = \sin(x)$. Dividing both sides by $\cos(x)$ (assuming $\cos(x) 
eq 0$),we get $	an(x) = 1$. We know that $	an(x) = 1 = 	an(\frac{\pi}{4})$. The general solution for $	an(x) = 	an(\alpha)$ is $x = n\pi + \alpha$,where $n \in Z$. Therefore,the general solution is $x = n\pi + \frac{\pi}{4}$,where $n \in Z$.

The general solution of $\cos(x) - \sin(x) = 0$ is

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