The geometry of Ni(CO)_4 and [Ni(PPh_3)_2Cl_2 | vedclass

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(C) $Ni(CO)_4$: The oxidation state of $Ni$ is $0$. The electronic configuration is $[Ar] 3d^{10} 4s^0$. Due to the strong field ligand $CO$,the elect

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both tetrahedral

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(C) $Ni(CO)_4$: The oxidation state of $Ni$ is $0$. The electronic configuration is $[Ar] 3d^{10} 4s^0$. Due to the strong field ligand $CO$,the electrons are paired,resulting in $sp^3$ hybridization. Thus,the geometry is tetrahedral.$[Ni(PPh_3)_2Cl_2]$: The oxidation state of $Ni$ is $+2$. The electronic configuration is $[Ar] 3d^8$. $PPh_3$ and $Cl^-$ are ligands that do not cause pairing of $d$-electrons in this specific complex,leading to $sp^3$ hybridization. Thus,the geometry is tetrahedral.

The geometry of $Ni(CO)_4$ and $[Ni(PPh_3)_2Cl_2]$ are

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