The graph between two temperature scales P an | vedclass

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Question

(B) The general formula for converting between two temperature scales is given by:$\frac{	ext{Reading on scale} - 	ext{Lower fixed point}}{	ext{Upp

Vedclass · Accepted Answer

$\frac{t_Q}{100}=\frac{t_P-30}{150}$

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(B) The general formula for converting between two temperature scales is given by:$\frac{	ext{Reading on scale} - 	ext{Lower fixed point}}{	ext{Upper fixed point} - 	ext{Lower fixed point}} = 	ext{Constant}$From the graph,for scale $P$,the lower fixed point is $30$ and the upper fixed point is $180$ (since $180 - 30 = 150$ divisions).For scale $Q$,the lower fixed point is $0$ and the upper fixed point is $100$ (since $100 - 0 = 100$ divisions).Applying the formula:$\frac{t_P - 30}{180 - 30} = \frac{t_Q - 0}{100 - 0}$Simplifying the expression:$\frac{t_P - 30}{150} = \frac{t_Q}{100}$

The graph between two temperature scales $P$ and $Q$ is shown in the figure. Between the upper fixed point and the lower fixed point,there are $150$ equal divisions on scale $P$ and $100$ divisions on scale $Q$. The relationship for conversion between the two scales is given by:

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