The pressure of a gas filled in the bulb of a | vedclass

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(C) For a constant volume gas thermometer,the temperature $T$ is related to the pressure $P$ by the linear relation: $T = \frac{P - P_0}{P_{100} - P_0

Vedclass · Accepted Answer

$49.5$

Vedclass · Answer

(C) For a constant volume gas thermometer,the temperature $T$ is related to the pressure $P$ by the linear relation: $T = \frac{P - P_0}{P_{100} - P_0} 	imes 100^{\circ} C$ Given: $P_0 = 27.50 \, cm$ of $Hg$ at $0^{\circ} C$ $P_{100} = 37.50 \, cm$ of $Hg$ at $100^{\circ} C$ $P = 32.45 \, cm$ of $Hg$ at unknown temperature $T$ Substituting the values: $T = \frac{32.45 - 27.50}{37.50 - 27.50} 	imes 100$ $T = \frac{4.95}{10.00} 	imes 100$ $T = 0.495 	imes 100 = 49.5^{\circ} C$ Thus,the unknown temperature is $49.5^{\circ} C$.

The pressure of a gas filled in the bulb of a constant volume gas thermometer at temperatures $0^{\circ} C$ and $100^{\circ} C$ are $27.50 \, cm$ and $37.50 \, cm$ of $Hg$ respectively. At an unknown temperature,the pressure is $32.45 \, cm$ of $Hg$. The unknown temperature is ........ $^{\circ} C$.

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