The graph shows how the magnification m produ | vedclass

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(D) For a thin lens,the magnification $m$ is given by the formula $m = \frac{f - v}{f}$,where $f$ is the focal length and $v$ is the image distance.Th

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$\frac{c}{b}$

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(D) For a thin lens,the magnification $m$ is given by the formula $m = \frac{f - v}{f}$,where $f$ is the focal length and $v$ is the image distance.This can be rewritten as $m = -\frac{1}{f}v + 1$.Comparing this equation with the linear equation $y = mx' + c'$ (where $m$ is the slope and $c'$ is the y-intercept),we identify the slope of the line as $-\frac{1}{f}$.From the provided graph,the slope of the line is the ratio of the vertical change to the horizontal change,which is $\frac{b}{c}$.Equating the two expressions for the slope: $-\frac{1}{f} = \frac{b}{c}$.Taking the magnitude,we get $|f| = \frac{c}{b}$.Therefore,the focal length of the lens is $\frac{c}{b}$.

The graph shows how the magnification $m$ produced by a convex thin lens varies with image distance $v$. What was the focal length of the used lens?

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