The gravitational potential energy of a body | vedclass

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(A) The gravitational potential energy of a body of mass $m$ at the surface of the earth (radius $R$) is given by $E = -\frac{GMm}{R}$.When the body i

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$0.4$

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(A) The gravitational potential energy of a body of mass $m$ at the surface of the earth (radius $R$) is given by $E = -\frac{GMm}{R}$.When the body is taken to a height $h = 150\% 	ext{ of } R$,we have $h = 1.5R$.The distance of the body from the center of the earth at this height is $R' = R + h = R + 1.5R = 2.5R$.The new gravitational potential energy $E'$ is given by $E' = -\frac{GMm}{R'} = -\frac{GMm}{2.5R}$.Substituting $E = -\frac{GMm}{R}$ into the expression for $E'$,we get $E' = \frac{E}{2.5} = 0.4E$.

The gravitational potential energy of a body on the surface of the earth is $E$. If the body is taken from the surface of the earth to a height equal to $150 \%$ of the radius of the earth,its gravitational potential energy is (in $E$)

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