The gyromagnetic ratio of an electron revolvi | vedclass

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(D) The gyromagnetic ratio is defined as the ratio of the magnetic dipole moment to the angular momentum of the electron,which is given by the formula

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$ \frac{1}{11} 	imes 10^{-29} \ kg $

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(D) The gyromagnetic ratio is defined as the ratio of the magnetic dipole moment to the angular momentum of the electron,which is given by the formula: $\gamma = \frac{e}{2m_e}$.Given,gyromagnetic ratio $\gamma = 8.8 	imes 10^{10} \ C \ kg^{-1}$.Charge of the electron $e = 1.6 	imes 10^{-19} \ C$.Rearranging the formula to solve for the mass of the electron $m_e$:$m_e = \frac{e}{2\gamma}$.Substituting the given values:$m_e = \frac{1.6 	imes 10^{-19}}{2 	imes 8.8 	imes 10^{10}}$.$m_e = \frac{1.6 	imes 10^{-19}}{17.6 	imes 10^{10}}$.$m_e = \frac{16}{176} 	imes 10^{-29} \ kg$.$m_e = \frac{1}{11} 	imes 10^{-29} \ kg$.Thus,the mass of the electron is $\frac{1}{11} 	imes 10^{-29} \ kg$.

The gyromagnetic ratio of an electron revolving in a circular orbit of a hydrogen atom is $ 8.8 \times 10^{10} \ C \ kg^{-1} $. What is the mass of the electron? Given the charge of the electron $ e = 1.6 \times 10^{-19} \ C $.

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