The heat change for the following reaction at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta E)$ is given by: $\Delta H = \Delta E + \Delta n_g RT$,w

Vedclass · Accepted Answer

Less than $7.3 \ kcal$

Vedclass · Answer

(C) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta E)$ is given by: $\Delta H = \Delta E + \Delta n_g RT$,where $\Delta n_g$ is the change in the number of moles of gaseous species.For the reaction: $A_2B_{(s)} 	o 2A_{(s)} + 1/2B_{2(g)}$,the value of $\Delta n_g = (1/2) - 0 = 0.5 \ mol$.Given: $\Delta H = +7.3 \ kcal$,$T = 298 \ K$,and $R \approx 0.002 \ kcal \ K^{-1} \ mol^{-1}$.Substituting the values: $\Delta E = \Delta H - \Delta n_g RT = 7.3 - (0.5 	imes 0.002 	imes 298) = 7.3 - 0.298 = 7.002 \ kcal$.Since $7.002 \ kcal < 7.3 \ kcal$,the heat change at constant volume $(\Delta E)$ is less than $7.3 \ kcal$.

The heat change for the following reaction at $298 \ K$ and at constant pressure is $+7.3 \ kcal$: $A_2B_{(s)} \to 2A_{(s)} + 1/2B_{2(g)}$,$\Delta H = +7.3 \ kcal$. The heat change at constant volume would be:

Similar Questions

In an adiabatic process,no transfer of heat takes place between the system and surroundings. Choose the correct option for the free expansion of an ideal gas under adiabatic conditions from the following:

For the reaction $FeCO_{3(s)} \to FeO_{(s)} + CO_{2(g)}$,$\Delta H = 82.8 \ kJ$ at $25 \ ^oC$. What is $\Delta U$ at $25 \ ^oC$ in $kJ$?

An ideal gas expands adiabatically against vacuum. Which of the following is correct for the given process?

For the reaction $PCl_{5(g)} \to PCl_{3(g)} + Cl_{2(g)}$,which of the following relations is correct?

Which of the following processes exhibits an increase in internal energy?

Vedclass Test Series

Exam Paper Generator

Online Exam Module