The height $y$ and the distance $x$ along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by $y = (8t - 5t^2) \ m$ and $x = 6t \ m$,where $t$ is in seconds. The angle with the horizontal at which the projectile was projected is:
- A$\tan^{-1}(3/4)$
- B$\tan^{-1}(4/3)$
- C$\sin^{-1}(3/4)$
- DNot obtainable from the given data
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