The height of a circular cylinder is increased $6$ times and the base area is decreased to $\frac{1}{9}$ of its value. The factor by which the lateral surface area of the cylinder increases is

  • A
    $2$
  • B
    $\frac{1}{2}$
  • C
    $\frac{2}{3}$
  • D
    $\frac{3}{2}$

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