The heights of two poles standing erect on a | vedclass

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(C) Let the two poles be $AB = 6 \, m$ and $CD = 11 \, m$ standing on a flat ground.The distance between their bases is $BD = 12 \, m$.Draw a line seg

Vedclass · Accepted Answer

$13$

Vedclass · Answer

(C) Let the two poles be $AB = 6 \, m$ and $CD = 11 \, m$ standing on a flat ground.The distance between their bases is $BD = 12 \, m$.Draw a line segment $AE$ parallel to $BD$ such that $E$ lies on $CD$.Then $AE = BD = 12 \, m$ and $ED = AB = 6 \, m$.Now,$CE = CD - ED = 11 \, m - 6 \, m = 5 \, m$.In the right-angled triangle $	riangle AEC$,by the Pythagorean theorem:$AC^2 = AE^2 + CE^2$$AC^2 = (12)^2 + (5)^2$$AC^2 = 144 + 25 = 169$$AC = \sqrt{169} = 13 \, m$.Thus,the distance between their tops is $13 \, m$.

The heights of two poles standing erect on a flat ground are $6 \, m$ and $11 \, m$. If the distance between their bases is $12 \, m$,find the distance between their tops.

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