The hybridisation involved in [CoF_6]^{3-} is | vedclass

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Question

(D) The central metal ion is $Co^{3+}$,which has an electronic configuration of $[Ar] 3d^6$.$F^-$ is a weak field ligand,so it does not cause pairing

Vedclass · Accepted Answer

$sp^3d^2$

Vedclass · Answer

(D) The central metal ion is $Co^{3+}$,which has an electronic configuration of $[Ar] 3d^6$.$F^-$ is a weak field ligand,so it does not cause pairing of electrons in the $3d$ orbitals.Therefore,the complex uses the outer $4d$ orbitals for hybridisation.For a coordination number of $6$,the hybridisation is $sp^3d^2$,resulting in an outer orbital high-spin complex.

$A. sp^3$	$(i). [Co(NH_3)_6]^{3+}$
$B. dsp^2$	$(ii). [Ni(CO)_4]$
$C. sp^3d^2$	$(iii). [Pt(NH_3)_2Cl_2]$
$D. d^2sp^3$	$(iv). [CoF_6]^{3-}$
	$(v). [Fe(CO)_5]$

The hybridisation involved in $[CoF_6]^{3-}$ is :

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The shape of the manganate ion $(MnO_4^{2-})$ is . . . . . . .

Match the following hybridization in Column $I$ with the corresponding coordination complexes in Column $II$.
$A. sp^3$ $(i). [Co(NH_3)_6]^{3+}$
$B. dsp^2$ $(ii). [Ni(CO)_4]$
$C. sp^3d^2$ $(iii). [Pt(NH_3)_2Cl_2]$
$D. d^2sp^3$ $(iv). [CoF_6]^{3-}$
$(v). [Fe(CO)_5]$

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What type of hybridization is present in $[Co(NH_3)_6]^{3+}$ complex?

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