The hybridisation of $S$ in $SF_{4}$ is

The increasing order of electronegativity of hybrid orbitals is ..........

Match List-$I$ with List-$II$ :

$LIST$-$I$ (Hybridization)	$LIST$-$II$ (Orientation in Space)
$A$. $sp^3$	$I$. Trigonal bipyramidal
$B$. $dsp^2$	$II$. Octahedral
$C$. $sp^3 d$	$III$. Tetrahedral
$D$. $sp^3 d^2$	$IV$. Square planar

Choose the correct answer from the options given below :

Which orbital is more electronegative among $sp$,$sp^2$,and $sp^3$? Why?

Which of the underlined atoms in the molecules shown below have $sp$-hybridization?
$(u) H_2\underline{C}=CH-CH_3$
$(v) CH_2=\underline{C}=CHCl$
$(w) CH_3-\underline{C}H_2^+$
$(x) H-C \equiv C-H$
$(y) CH_3-\underline{C} \equiv N$
$(z) (CH_3)_2C=\underline{N}-NH_2$

In which of the following sets of molecules,do the central atoms have the same hybridisation?