The hybridisation of metals involved in the f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In $[Mn(CN)_6]^{3-}$,$Mn$ is in $+3$ oxidation state ($3d^4$ configuration). Since $CN^-$ is a strong field ligand,it causes the pairing of $3d$ e

Vedclass · Accepted Answer

$d^2sp^3, sp^3d^2$

Vedclass · Answer

(D) In $[Mn(CN)_6]^{3-}$,$Mn$ is in $+3$ oxidation state ($3d^4$ configuration). Since $CN^-$ is a strong field ligand,it causes the pairing of $3d$ electrons,making two $3d$-orbitals vacant. These two $3d$,one $4s$,and three $4p$-orbitals hybridise to give $d^2sp^3$ hybridisation. In $[CoF_6]^{3-}$,$Co$ is in $+3$ oxidation state ($3d^6$ configuration). Since $F^-$ is a weak field ligand,it cannot cause the pairing of unpaired $3d$ electrons. Thus,one $4s$,three $4p$,and two $4d$-orbitals hybridise to give $sp^3d^2$ hybridisation.

The hybridisation of metals involved in the following complexes,$[Mn(CN)_6]^{3-}$ and $[CoF_6]^{3-}$,are respectively:

Similar Questions

In an octahedral structure,which pair of $d$-orbitals is involved in ${d^2}sp^3$ hybridization?

What type of geometry and magnetic nature is present in the complex $[NiCl_4]^{2-}$?

Which of the following complexes exhibits a square planar geometry?

In the formation of $K_4[Fe(CN)_6]$,the hybridisation involved is

Which of the following is not a square planar complex?

Vedclass Test Series

Exam Paper Generator

Online Exam Module