Which of the following is not a square planar | vedclass

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(D) $1$. $[AgF_4]^-$: $Ag(III)$ is a $d^8$ metal ion,which typically forms square planar complexes.$2$. $[AuCl_4]^-$: $Au(III)$ is a $d^8$ metal ion,w

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$[NiCl_2(PMe_3)_2]$

Vedclass · Answer

(D) $1$. $[AgF_4]^-$: $Ag(III)$ is a $d^8$ metal ion,which typically forms square planar complexes.$2$. $[AuCl_4]^-$: $Au(III)$ is a $d^8$ metal ion,which forms square planar complexes.$3$. $[RhCl(PPh_3)_3]$: This is a $16$-electron $Rh(I)$ complex,which is square planar (Wilkinson's catalyst).$4$. $[NiCl_2(PMe_3)_2]$: $Ni(II)$ is a $d^8$ ion. While many $Ni(II)$ complexes are square planar,the geometry depends on the ligand field strength. For $[NiCl_2(PMe_3)_2]$,the complex is tetrahedral due to the steric bulk of the $PMe_3$ ligands and the weak field nature of $Cl^-$ ligands.

Which of the following is not a square planar complex?

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Select the incorrect match.

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