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(D) The formula for Bulk modulus $K$ is given by $K = -\frac{\Delta p}{\Delta V / V}$.We are given the Bulk modulus $K = 2100 \, MPa = 2100 	imes 10^

Vedclass · Accepted Answer

$168$

Vedclass · Answer

(D) The formula for Bulk modulus $K$ is given by $K = -\frac{\Delta p}{\Delta V / V}$.We are given the Bulk modulus $K = 2100 \, MPa = 2100 	imes 10^3 \, kPa$.The fractional change in volume is $\frac{\Delta V}{V} = 0.008 \, \% = \frac{0.008}{100} = 8 	imes 10^{-5}$.To find the increase in pressure $\Delta p$, we rearrange the formula: $\Delta p = K 	imes \left( \frac{\Delta V}{V} ight)$.Substituting the values: $\Delta p = (2100 	imes 10^3 \, kPa) 	imes (8 	imes 10^{-5})$.$\Delta p = 2100 	imes 8 	imes 10^{-2} \, kPa = 21 	imes 8 \, kPa = 168 \, kPa$.

The increase in pressure required to decrease the $200 \, L$ volume of a liquid by $0.008 \, \%$ in $kPa$ is (Bulk modulus of the liquid $= 2100 \, MPa$)

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