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(B) The instantaneous current is given by the equation $I = I_{0} \sin (\omega t + \phi)$,where $I_{0}$ is the peak current.Comparing this with the gi

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$\frac{5}{\sqrt{2}} 	ext{ A}$

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(B) The instantaneous current is given by the equation $I = I_{0} \sin (\omega t + \phi)$,where $I_{0}$ is the peak current.Comparing this with the given equation $I = 5 \sin (\omega t + \phi)$,we find the peak current $I_{0} = 5 	ext{ A}$.The root mean square $(rms)$ value of an alternating current is related to the peak current by the formula $I_{rms} = \frac{I_{0}}{\sqrt{2}}$.Substituting the value of $I_{0}$,we get $I_{rms} = \frac{5}{\sqrt{2}} 	ext{ A}$.

The instantaneous value of an $AC$ is given by $I = 5 \sin (\omega t + \phi) \text{ A}$. The rms value of current is

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