The ionisation energy of an electron in the g | vedclass

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(B) The energy required to remove the first electron from a neutral helium atom $(He)$ is given as $24.6 eV$.After the first electron is removed,the r

Vedclass · Accepted Answer

$79$

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(B) The energy required to remove the first electron from a neutral helium atom $(He)$ is given as $24.6 eV$.After the first electron is removed,the remaining ion is $He^+$,which is a hydrogen-like species with atomic number $Z = 2$.The energy required to remove the second electron from the ground state of $He^+$ is given by the formula $E = Z^2 	imes 13.6 eV$.Substituting $Z = 2$,we get $E = (2)^2 	imes 13.6 eV = 4 	imes 13.6 eV = 54.4 eV$.The total energy required to remove both electrons is the sum of the energy to remove the first and the second electron.Total Energy $= 24.6 eV + 54.4 eV = 79 eV$.

The ionisation energy of an electron in the ground state of a helium atom is $24.6 eV$. The energy required to remove both electrons is: (in $eV$)

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