Which of the following atoms has the lowest i | vedclass

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(C) Ionization potential is the energy required to remove the most loosely bound electron from an isolated gaseous atom.Among the given atoms,$_{55}^{

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$_{55}^{133}Cs$

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(C) Ionization potential is the energy required to remove the most loosely bound electron from an isolated gaseous atom.Among the given atoms,$_{55}^{133}Cs$ (Cesium) is an alkali metal located in the first group and the sixth period of the periodic table.It has the largest atomic size among the options provided,which means the outermost electron is at the greatest distance from the nucleus.Due to the increased distance,the electrostatic force of attraction between the nucleus and the valence electron is the weakest.Consequently,the energy required to remove this electron is the lowest for $_{55}^{133}Cs$.

List-$I$	List-$II$
$1$. Nitrogen molecules	$(A)$ Continuous spectrum
$2$. Incandescent solids	$(B)$ Absorption spectrum
$3$. Fraunhofer lines	$(C)$ Band spectrum
$4$. Electric arc between iron rods	$(D)$ Emission spectrum

$1$. Burning candle	$i$. Line spectrum
$2$. Sodium vapour	$ii$. Continuous spectrum
$3$. Bunsen flame	$iii$. Band spectrum
$4$. Dark lines in solar spectrum	$iv$. Absorption spectrum

Which of the following atoms has the lowest ionization potential?

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