The irrational number which is not a surd is | vedclass

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Question

(A) surd is defined as an irrational root of a rational number,such as $\sqrt[n]{x}$,where $x$ is a rational number and the result is irrational.$\pi$

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$\pi$

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(A) surd is defined as an irrational root of a rational number,such as $\sqrt[n]{x}$,where $x$ is a rational number and the result is irrational.$\pi$ is a transcendental number. It is irrational,but it cannot be expressed as the $n$-th root of any rational number. Therefore,$\pi$ is an irrational number that is not a surd.$\sqrt{16} = 4$,which is a rational number.$\sqrt{8} = 2\sqrt{2}$,which is a surd.$3\sqrt{27} = 3 	imes 3\sqrt{3} = 9\sqrt{3}$,which is a surd.Thus,the correct option is $A$.

Part $I$	Part $II$
$1. \text{l.c.m.}(8, 16, 24)$	$a. 36$
$2. \text{g.c.d.}(8, 16, 24)$	$b. 48$
$3. \text{l.c.m.}(6, 12, 18)$	$c. 8$
$4. \text{g.c.d.}(6, 12, 18)$	$d. 12$
	$e. 6$

The irrational number which is not a surd is ...............

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Part $I$ Part $II$

$1. \text{l.c.m.}(8, 16, 24)$ $a. 36$

$2. \text{g.c.d.}(8, 16, 24)$ $b. 48$

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