(B) According to the Work-Energy Theorem,the work done by the braking force is equal to the change in kinetic energy of the car.$W = \Delta KE$Since t

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(B) According to the Work-Energy Theorem,the work done by the braking force is equal to the change in kinetic energy of the car.$W = \Delta KE$Since the cars come to a stop,the work done by the braking force is $W = -F \cdot S$,where $F$ is the braking force and $S$ is the stopping distance.For car $A$: $F_{A} \cdot S_{A} = KE_{A} \implies F_{A} \cdot 1000 = 100 \implies F_{A} = 0.1 \ N$.For car $B$: $F_{B} \cdot S_{B} = KE_{B} \implies F_{B} \cdot 1500 = 225 \implies F_{B} = 225 / 1500 = 0.15 \ N$.Now,calculating the ratio $F_{A} / F_{B} = 0.1 / 0.15 = 10 / 15 = 2/3$.

Class 11 Physics Work, Energy, Power and Collision Work Energy Theorem and Conservation of Mechanical Energy

Medium

The kinetic energies of two similar cars $A$ and $B$ are $100 \ J$ and $225 \ J$ respectively. On applying brakes,car $A$ stops after $1000 \ m$ and car $B$ stops after $1500 \ m$. If $F_{A}$ and $F_{B}$ are the forces applied by the brakes on cars $A$ and $B$,respectively,then the ratio $F_{A} / F_{B}$ is:

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A
$3/2$
B
$2/3$
C
$1/3$
D
$1/2$

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Class 11

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Work, Energy, Power and Collision

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Work Energy Theorem and Conservation of Mechanical Energy

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Medium

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EasyIIT 1973

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