The length,breadth,and thickness of a metal s | vedclass

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Question

(A) Given: $L = 4.234 \; m$,$B = 1.005 \; m$,$T = 2.01 \; cm = 0.0201 \; m$.The surface area $A$ of a rectangular sheet is given by $A = 2(L 	imes B

Vedclass · Accepted Answer

$8.72 \; m^{2}, 0.0855 \; m^{3}$

Vedclass · Answer

(A) Given: $L = 4.234 \; m$,$B = 1.005 \; m$,$T = 2.01 \; cm = 0.0201 \; m$.The surface area $A$ of a rectangular sheet is given by $A = 2(L 	imes B + B 	imes T + T 	imes L)$.$A = 2(4.234 	imes 1.005 + 1.005 	imes 0.0201 + 0.0201 	imes 4.234)$$A = 2(4.25517 + 0.0202005 + 0.0851034) = 2(4.3604739) = 8.7209478 \; m^{2}$.Rounding to the least number of significant figures (which is $3$ in $2.01 \; cm$),we get $A = 8.72 \; m^{2}$.The volume $V$ is given by $V = L 	imes B 	imes T$.$V = 4.234 	imes 1.005 	imes 0.0201 = 0.085531443 \; m^{3}$.Rounding to the least number of significant figures $(3)$,we get $V = 0.0855 \; m^{3}$.

The length,breadth,and thickness of a metal sheet are $4.234 \; m$,$1.005 \; m$,and $2.01 \; cm$ respectively. Then the area and volume of the sheet are:

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