The length of a closed and an open pipe is th | vedclass

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Question

(A) For an open pipe of length $L$,the frequency of the $n^{	ext{th}}$ overtone is given by $f_{	ext{open}} = (n+1) \frac{v}{2L}$,where $n = 0, 1, 2

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$\frac{(2n+1)}{2(n+1)}$

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(A) For an open pipe of length $L$,the frequency of the $n^{	ext{th}}$ overtone is given by $f_{	ext{open}} = (n+1) \frac{v}{2L}$,where $n = 0, 1, 2, \dots$.For a closed pipe of length $L$,the frequency of the $n^{	ext{th}}$ overtone is given by $f_{	ext{closed}} = (2n+1) \frac{v}{4L}$,where $n = 0, 1, 2, \dots$.The ratio of the frequency of the $n^{	ext{th}}$ overtone for the closed pipe to that of the open pipe is:$	ext{Ratio} = \frac{f_{	ext{closed}}}{f_{	ext{open}}} = \frac{(2n+1) \frac{v}{4L}}{(n+1) \frac{v}{2L}}$$	ext{Ratio} = \frac{(2n+1)}{4L} 	imes \frac{2L}{(n+1)} = \frac{2n+1}{2(n+1)}$.

The length of a closed and an open pipe is the same. The ratio of the frequency of the $n^{\text{th}}$ overtone for the closed pipe to that of the open pipe is (Neglect end correction).

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