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(C) Let the side of the square be $a$. In a square, the diagonal $d$ is related to the side $a$ by the formula $d = a \sqrt{2}$. Given that the diagon

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$3$

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(C) Let the side of the square be $a$. In a square, the diagonal $d$ is related to the side $a$ by the formula $d = a \sqrt{2}$. Given that the diagonal $d = 6$, we have: $a \sqrt{2} = 6$ $a = \frac{6}{\sqrt{2}}$ To rationalize the denominator, multiply the numerator and denominator by $\sqrt{2}$: $a = \frac{6 	imes \sqrt{2}}{\sqrt{2} 	imes \sqrt{2}} = \frac{6 \sqrt{2}}{2} = 3 \sqrt{2}$. Therefore, the length of the side of the square is $3 \sqrt{2}$.

The length of a diagonal of a square is $6$. Then, the length of its sides is $\ldots \ldots \ldots$ (in $\sqrt{2}$)

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