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(B) Let the height of the wall be $h$ feet. The length of the ladder is also $h$ feet.When the ladder is placed on a $2$-feet tall stool at a distance

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$26$

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(B) Let the height of the wall be $h$ feet. The length of the ladder is also $h$ feet.When the ladder is placed on a $2$-feet tall stool at a distance of $10$ feet from the wall,the vertical height covered by the ladder against the wall is $(h - 2)$ feet.This forms a right-angled triangle where the base is $10$ feet,the perpendicular height is $(h - 2)$ feet,and the hypotenuse (the ladder) is $h$ feet.According to the Pythagorean theorem: $h^2 = 10^2 + (h - 2)^2$.$h^2 = 100 + (h^2 - 4h + 4)$.$h^2 = 100 + h^2 - 4h + 4$.Subtracting $h^2$ from both sides: $0 = 104 - 4h$.$4h = 104$.$h = 26$ feet.Thus,the height of the wall is $26$ feet.

The length of a ladder exactly equals the height of a wall. If the ladder is placed on a $2$-feet tall stool placed $10$ feet away from the wall,its tip just touches the top of the wall. The height of the wall in feet is

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