The length of a ladder is 6 ,m and it leans o | vedclass

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(A) Let the length of the ladder be the hypotenuse $c = 6 \,m$.Let the height reached on the wall be one leg $a = 3.6 \,m$.Let the distance from the b

Vedclass · Accepted Answer

$4.8$

Vedclass · Answer

(A) Let the length of the ladder be the hypotenuse $c = 6 \,m$.Let the height reached on the wall be one leg $a = 3.6 \,m$.Let the distance from the base of the wall to the lower end of the ladder be $b$.According to the Pythagorean theorem for a right-angled triangle formed by the wall,the ground,and the ladder:$a^2 + b^2 = c^2$$(3.6)^2 + b^2 = 6^2$$12.96 + b^2 = 36$$b^2 = 36 - 12.96$$b^2 = 23.04$$b = \sqrt{23.04} = 4.8 \,m$.Thus,the distance is $4.8 \,m$.

The length of a ladder is $6 \,m$ and it leans on a wall to reach the height of $3.6 \,m$. Find the distance in $m$ between the lower end of the ladder and the base of the wall.

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