The length of a rectangle is 2,cm less than 3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the breadth of the rectangle be $x\,cm$.Then,by the given condition,the length of the rectangle is $(3x - 2)\,cm$.Now,by the data,the area of

Vedclass · Accepted Answer

$28$

Vedclass · Answer

(C) Let the breadth of the rectangle be $x\,cm$.Then,by the given condition,the length of the rectangle is $(3x - 2)\,cm$.Now,by the data,the area of the rectangle is $280\,cm^2$.$	herefore$ Area of rectangle $= 280$$	herefore$ Length $	imes$ Breadth $= 280$$	herefore (3x - 2)(x) = 280$$	herefore 3x^2 - 2x = 280$$	herefore 3x^2 - 2x - 280 = 0$$	herefore (3x + 28)(x - 10) = 0$$	herefore 3x + 28 = 0$ or $x - 10 = 0$$	herefore x = -\frac{28}{3}$ or $x = 10$As $x$ is the breadth of a rectangle,it cannot be negative.$	herefore x = -\frac{28}{3}$ is not possible.$	herefore x = 10$Now,the length of the rectangle $= 3x - 2 = 3(10) - 2 = 28\,cm$.Hence,the length of the given rectangle is $28\,cm$.

The length of a rectangle is $2\,cm$ less than $3$ times its breadth. If its area is $280\,cm^2$,then find its length.

Similar Questions

If one of the roots of the quadratic equation $x^{2}-ax-8=0$ is $-4$,then $a = \ldots \ldots \ldots \ldots$.

Which constant should be added and subtracted to solve the quadratic equation $4x^{2} - \sqrt{3}x - 5 = 0$ by the method of completing the square?

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $4x^{2}-6x+2=0$.

If both the roots of a quadratic equation $ax^2 + bx + c = 0$ $(a \neq 0)$ are equal,then ..... .

Solve the following equation using the method of factorization and write its solution set: $\frac{1}{x-2}+\frac{1}{x+3}=\frac{7}{2x}$ $(x \neq 2, x \neq -3, x \neq 0)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module