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(B) Let the radius of the circle be $r$ and the side of the square be $a = 22\, cm$.Given that the circumference of the circle is equal to the area of

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$26$

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(B) Let the radius of the circle be $r$ and the side of the square be $a = 22\, cm$.Given that the circumference of the circle is equal to the area of the square:$2\pi r = a^2$$2 	imes \frac{22}{7} 	imes r = (22)^2$$2 	imes \frac{22}{7} 	imes r = 484$$r = \frac{484 	imes 7}{2 	imes 22} = \frac{484 	imes 7}{44} = 11 	imes 7 = 77\, cm$.The diameter of the circle is $d = 2r = 2 	imes 77 = 154\, cm$.The length of the rectangle $(l)$ is twice the diameter of the circle:$l = 2 	imes d = 2 	imes 154 = 308\, cm$.The perimeter of the rectangle is given as $668\, cm$:$2(l + b) = 668$$l + b = 334$$308 + b = 334$$b = 334 - 308 = 26\, cm$.Thus,the breadth of the rectangle is $26\, cm$.

The length of a rectangle is twice the diameter of a circle. The circumference of the circle is equal to the area of a square of side $22\, cm$. What is the breadth of the rectangle if its perimeter is $668\, cm$? (in $cm$)

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