The length of each side of an equilateral tri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The area of an equilateral triangle is given by the formula: $	ext{Area} = \frac{\sqrt{3}}{4} 	imes (	ext{side})^2$.Given that the area is $9 \

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) The area of an equilateral triangle is given by the formula: $	ext{Area} = \frac{\sqrt{3}}{4} 	imes (	ext{side})^2$.Given that the area is $9 \sqrt{3} 	ext{ cm}^2$,we set up the equation:$9 \sqrt{3} = \frac{\sqrt{3}}{4} 	imes (	ext{side})^2$.Dividing both sides by $\sqrt{3}$,we get:$9 = \frac{1}{4} 	imes (	ext{side})^2$.Multiplying both sides by $4$,we get:$(	ext{side})^2 = 36$.Taking the square root of both sides,we find:$	ext{side} = \sqrt{36} = 6 	ext{ cm}$.

The length of each side of an equilateral triangle having an area of $9 \sqrt{3} \text{ cm}^2$ is (in $\text{cm}$):

Similar Questions

The sides of a triangle are $56 \ cm$,$60 \ cm$,and $52 \ cm$ long. Then the area of the triangle is (in $cm^2$)

Write True or False and justify your answer.
If the side of a rhombus is $10 \, cm$ and one diagonal is $16 \, cm$,the area of the rhombus is $96 \, cm^2$.

In parallelogram $ABCD$,$AB = 9 \, cm$,$BC = 10 \, cm$ and $AC = 17 \, cm$,then find its area. (in $, cm^2$)

Area of a square $= (........... )^{2}.$

Area of a trapezium $=$ .........

Vedclass Test Series

Exam Paper Generator

Online Exam Module