The length of the common chord of the circles $(x - a)^2 + (y - b)^2 = c^2$ and $(x - b)^2 + (y - a)^2 = c^2$ is

  • A
    $\sqrt{4c^2 - 2(a - b)^2}$
  • B
    $\sqrt{4c^2 + 2(a - b)^2}$
  • C
    $\sqrt{4c^2 - 2(a + b)^2}$
  • D
    $\sqrt{4c^2 + 2(a + b)^2}$

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Similar Questions

Choose the correct option regarding the following statements :
Statement $I$: The length of the common chord of the circles $x^2+y^2+ax+by+c=0$ and $x^2+y^2+bx+ay+c=0$ is equal to $\frac{\sqrt{(a+b)^2-8c}}{2}$.
Statement $II$: If two circles intersect at two distinct points,then their radical axis is their common chord.

The length of the common chord of the circles $x^2 + y^2 = 12$ and $x^2 + y^2 - 4x + 3y - 2 = 0$ is (in $\sqrt{2}$)

Find the distance from the center of the circle $x^2 + y^2 = 2x$ to the common chord of the circles $x^2 + y^2 + 5x - 8y + 1 = 0$ and $x^2 + y^2 - 3x + 7y - 25 = 0$.

The length of the common chord of the two circles $(x-a)^2+y^2=a^2$ and $x^2+(y-b)^2=b^2$ is

If the circle $S \equiv x^2+y^2-4=0$ intersects another circle $S^{\prime}=0$ of radius $\frac{5 \sqrt{2}}{2}$ in such a manner that the common chord is of maximum length with slope equal to $\frac{1}{4}$,then the centre of $S^{\prime}=0$ is

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