(C) The length of the tangent from a point $(x_1, y_1)$ to a circle $x^2+y^2+2gx+2fy+c=0$ is given by $\sqrt{x_1^2+y_1^2+2gx_1+2fy_1+c}$.Given the cir

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(C) The length of the tangent from a point $(x_1, y_1)$ to a circle $x^2+y^2+2gx+2fy+c=0$ is given by $\sqrt{x_1^2+y_1^2+2gx_1+2fy_1+c}$.Given the circle equation $x^2+y^2-2x+4y-11=0$ and the point $(1,3)$.Substituting the values into the formula:Length $= \sqrt{1^2+3^2-2(1)+4(3)-11}$$= \sqrt{1+9-2+12-11}$$= \sqrt{22-13}$$= \sqrt{9}$$= 3$

Class 11 Mathematics 10-1.Circle and System of Circles Tangent and normal to a circle

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The length of the tangent drawn to the circle $x^2+y^2-2x+4y-11=0$ from the point $(1,3)$ is:

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A
$1$
B
$2$
C
$3$
D
$4$

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10-1.Circle and System of Circles

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The length of the tangent drawn to the circle $x^2+y^2-2x+4y-11=0$ from the point $(1,3)$ is:

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