The lengths of the sides and the diagonal of an isosceles trapezium form a two-element set $\{a, b\}$. If $a > b$,then $a / b$ equals

  • A
    $\frac{1}{2}(\sqrt{5}+1)$
  • B
    $\frac{1}{2}(\sqrt{6}+\sqrt{2})$
  • C
    $\sqrt{3}$
  • D
    $\sqrt{2}$

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