The lower reactivity of the chlorine atom in $CH_2 = CH - Cl$ is due to:

$(i)$ chlorobenzene is mono-nitrated to $M$.
$(ii)$ nitrobenzene is mono-chlorinated to $N$.
$(iii)$ anisole is mono-nitrated to $P$.
$(iv)$ $2-$nitrochlorobenzene is mono-nitrated to $Q$.
Out of $M$,$N$,$P$ and $Q$,the compound that undergoes reaction with $aq. NaOH$ fastest is:

In the reaction given below,the major product formed is

What is the product $X$ in the following Wurtz-Fittig reaction?

The decreasing order of reactivity of the given compounds towards nucleophilic substitution with aqueous $NaOH$ is:
$(I)$ $1$-bromo-$3$-nitrobenzene
$(II)$ $1$-bromo-$2,4,6$-trinitrobenzene
$(III)$ $1$-bromo-$4$-nitrobenzene
$(IV)$ $1$-bromo-$2,4$-dinitrobenzene

$[P]$ on treatment with $Br_{2}/FeBr_{3}$ in $CCl_{4}$ produced a single isomer $C_{8}H_{7}O_{2}Br$ while heating $[P]$ with sodalime gave toluene. The compound $[P]$ is: