The light of wavelength $6328 \ \mathring{A}$ is incident on a slit of width $0.2 \ mm$ perpendicularly. The angular width of the central maxima will be.....$^o$

Light of wavelength $5000 \text{ Å}$ is incident normally on a slit. The first minimum of the diffraction pattern is observed to lie at a distance of $5 \text{ mm}$ from the central maximum on a screen placed at a distance of $2 \text{ m}$ from the slit. The width of the slit is: (in $\text{ cm}$)

Visible light of wavelength $6000 \times 10^{-8} \; cm$ falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at $60^{\circ}$ from the central maximum. If the first minimum is produced at $\theta_{1}$,then $\theta_{1}$ is close to.....$^{\circ}$

Maximum diffraction takes place in a given slit for

If the width of the slit is $a$,then the value of the first secondary maximum in a single slit diffraction pattern is given by:

In a single slit diffraction pattern, the distance between the first minimum on the left and the first minimum on the right is $5 \,mm$. The screen on which the diffraction pattern is obtained is at a distance of $80 \,cm$ from the slit. The wavelength used is $6000 \mathring{A}$. The width of the slit is (in $\,mm$)