The logic operation performed by the followin | vedclass

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(B) The given circuit consists of a $NAND$ gate followed by a $NOR$ gate where both inputs of the $NOR$ gate are connected to the output of the $NAND$

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$AND$

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(B) The given circuit consists of a $NAND$ gate followed by a $NOR$ gate where both inputs of the $NOR$ gate are connected to the output of the $NAND$ gate.Let the inputs be $A$ and $B$. The output of the $NAND$ gate is $Y_1 = \overline{A \cdot B}$.This $Y_1$ is fed as both inputs to the $NOR$ gate. The output of a $NOR$ gate with inputs $X$ and $X$ is $Y = \overline{X + X} = \overline{X}$.Substituting $X = Y_1 = \overline{A \cdot B}$, we get $Y = \overline{\overline{A \cdot B}} = A \cdot B$.The expression $Y = A \cdot B$ corresponds to the logic operation of an $AND$ gate.

$A$	$B$	$Y$
$1$	$1$	$0$
$1$	$0$	$0$
$0$	$1$	$0$
$0$	$0$	$1$

The logic operation performed by the following circuit is

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