The lowest O-O bond length in the following m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To determine the $O-O$ bond length, we look at the bond order of each species:$1$. For $O_2$, the bond order is $2.0$ (bond length $\approx 121

Vedclass · Accepted Answer

$O_2$

Vedclass · Answer

(B) To determine the $O-O$ bond length, we look at the bond order of each species:$1$. For $O_2$, the bond order is $2.0$ (bond length $\approx 121 	ext{ pm}$).$2$. For $O_3$, the bond order is $1.5$ (resonance hybrid, bond length $\approx 128 	ext{ pm}$).$3$. For $H_2O_2$, the bond order is $1.0$ (bond length $\approx 148 	ext{ pm}$).$4$. For $O_2F_2$, the bond order is $1.0$, but due to the high electronegativity of fluorine and repulsion between lone pairs, the $O-O$ bond is significantly elongated (bond length $\approx 149 	ext{ pm}$).Comparing these, $O_2$ has the highest bond order and therefore the shortest $O-O$ bond length.

The lowest $O-O$ bond length in the following molecules is:

Similar Questions

Bond order of $He_{2}$, $He_{2}^{+}$ and $He_{2}^{2+}$ are respectively:

Which one of the following species is diamagnetic in nature?

Which of the following electronic configurations is correct for the given species?

Answer the following questions:
$(i)$ Give the molecular orbitals and their types formed by $LCAO$ from $2s, 2p_{x}, 2p_{y}$ and $2p_{z}$ atomic orbitals.
$(ii)$ Provide the energy order of molecular orbitals for $Li_{2}, Be_{2}, C_{2}, N_{2}, O_{2}$ and $F_{2}$.

The diamagnetic species is

Vedclass Test Series

Exam Paper Generator

Online Exam Module