Which of the following electronic configurati | vedclass

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(A) According to Molecular Orbital Theory $(MOT)$,for homonuclear and heteronuclear diatomic molecules with $14$ or fewer electrons,the order of energ

Vedclass · Accepted Answer

$CO : \sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2px^2, \pi 2py^2, \sigma 2pz^2$

Vedclass · Answer

(A) According to Molecular Orbital Theory $(MOT)$,for homonuclear and heteronuclear diatomic molecules with $14$ or fewer electrons,the order of energy is $\sigma 1s For molecules with more than $14$ electrons,the order is $\sigma 1s $CO$ ($14$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2px^2, \pi 2py^2, \sigma 2pz^2$.$CN^-$ ($14$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2px^2, \pi 2py^2, \sigma 2pz^2$.$NO$ ($15$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2pz^2, \pi 2px^2, \pi 2py^2, \pi^* 2px^1$.$N_2^+$ ($13$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2px^2, \pi 2py^2, \sigma 2pz^1$.All given options represent correct configurations based on the $MOT$ energy order.

Which of the following electronic configurations is correct for the given species?

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