Which of the following has unpaired electron( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The molecular orbital configuration for $O_2^-$ (total $17$ electrons) is: $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_x)^2(\pi 2p_y)^2(\pi 2p_z)^2(

Vedclass · Accepted Answer

$O_2^-$

Vedclass · Answer

(B) The molecular orbital configuration for $O_2^-$ (total $17$ electrons) is: $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_x)^2(\pi 2p_y)^2(\pi 2p_z)^2(\pi^* 2p_y)^2(\pi^* 2p_z)^1$.Since there is one unpaired electron in the $\pi^* 2p_z$ orbital,$O_2^-$ is paramagnetic.For $N_2$ ($14$ electrons): $(\sigma 1s)^2(\sigma^* 1s)^2(\sigma 2s)^2(\sigma^* 2s)^2(\pi 2p_y)^2(\pi 2p_z)^2(\sigma 2p_x)^2$ (all paired).For $N_2^{2+}$ ($12$ electrons): $(\sigma 1s)^2(\sigma^* 1s)^2(\sigma 2s)^2(\sigma^* 2s)^2(\pi 2p_y)^2(\pi 2p_z)^2$ (all paired).For $O_2^{2-}$ ($18$ electrons): $(\sigma 1s)^2(\sigma^* 1s)^2(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_x)^2(\pi 2p_y)^2(\pi 2p_z)^2(\pi^* 2p_y)^2(\pi^* 2p_z)^2$ (all paired).

Which of the following has unpaired electron$(s)$?

Similar Questions

Give the electron configuration,bond order,magnetic property,and energy diagram for the beryllium $(Be_{2})$ molecule and discuss its existence.

Which of the following is planar due to back bonding?

Among $KO_2$,$KAlO_2$,$CaO_2$ and $NO_2^+$,unpaired electron is present in

What is the number of unpaired electron$(s)$ in the highest occupied molecular orbital $(HOMO)$ of the following species: $N_2$,$N_2^{+}$,$O_2$,$O_2^{+}$?

Which of the following pairs of species have the same number of unpaired electrons but different bond orders?

Vedclass Test Series

Exam Paper Generator

Online Exam Module