The magnetic field at the centre of a single-turn circular coil of a given length of wire carrying a current $I$ is $B$. If the same wire is bent into a circular coil of two turns and the same current $I$ is passed through it,the new magnetic field at the centre will be:

  • A
    $\frac{B}{2}$
  • B
    $16B$
  • C
    $4B$
  • D
    $\frac{B}{4}$

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