(D) The magnetic moment $\mu$ is given by the formula $\mu = \sqrt{n(n + 2)} \ BM$,where $n$ is the number of unpaired electrons.Given $\mu = 2.83 \ B

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(D) The magnetic moment $\mu$ is given by the formula $\mu = \sqrt{n(n + 2)} \ BM$,where $n$ is the number of unpaired electrons.Given $\mu = 2.83 \ BM$.$2.83 = \sqrt{n(n + 2)}$Squaring both sides,we get $8 = n(n + 2)$.$n^2 + 2n - 8 = 0$.Solving the quadratic equation: $(n + 4)(n - 2) = 0$.Since $n$ must be positive,$n = 2$.

Class 12 Chemistry d-and f-Block Elements General Characteristics

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The magnetic moment of a metal ion of the first transition series is $2.83 \ BM$. Therefore,it will have how many unpaired electrons?

A
$6$
B
$4$
C
$3$
D
$2$

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d-and f-Block Elements

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General Characteristics

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The magnetic moment of a metal ion of the first transition series is $2.83 \ BM$. Therefore,it will have how many unpaired electrons?

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(Atomic numbers: $Fe=26, Co=27, Mn=25, Cr=24$)