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Question

(B) The reaction between $p$-cresol ($4$-methylphenol) and benzene diazonium chloride in a mild basic medium is an electrophilic aromatic substitution

Vedclass · Accepted Answer

$2-$(phenylazo)$-4-$methylphenol.

Vedclass · Answer

(B) The reaction between $p$-cresol ($4$-methylphenol) and benzene diazonium chloride in a mild basic medium is an electrophilic aromatic substitution reaction,specifically a coupling reaction.In $p$-cresol,the para position is already occupied by a methyl group $(-CH_3)$.Therefore,the electrophile (benzene diazonium ion,$C_6H_5N_2^+$) attacks the ortho position relative to the hydroxyl $(-OH)$ group.The resulting product is $2$-(phenylazo)-$4$-methylphenol.

The main product of the following reaction will be:

Similar Questions

In the given reaction,the compound $C$ is:
$C_6H_5OH$ $\xrightarrow{NaOH} (A)$ $\xrightarrow{CO_2, 140 \ ^oC, (4-7 \ atm)} (B)$ $\xrightarrow{HCl} (C)$

The correct order of acidic strength of the following compounds:
$A.$ Phenol
$B.$ Cresol
$C.$ $m-$Nitrophenol
$D.$ $p-$Nitrophenol

What is the product formed in the following reaction?
$C_6H_5OH + CCl_4 \xrightarrow[(2) \ H^{+}]{(1) \ NaOH}$

Carbolic acid is oxidised by acidified sodium dichromate to give

Among $(i)-(iii)$,the boiling point follows the order:

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