The major product $Y$ in the following reaction is:

The product $(B)$ in the given reaction is:

Assertion : Isobutanal does not give iodoform test.
Reason : It does not have $\alpha - $ hydrogen.

Match the example given in Column-$I$ with the name of the reaction in Column-$II$.

Column-$I$ (Example)	Column-$II$ (Reaction)
$(A)$ $CH_3COCl + H_2 \xrightarrow{Pd-C/BaSO_4} CH_3CHO$	$(1)$ Friedel-Crafts acylation
$(B)$ $C_6H_5CHO \xrightarrow{NaOH} C_6H_5CH_2OH + C_6H_5COONa$	$(2)$ $HVZ$ reaction
$(C)$ $C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3$	$(3)$ Aldol condensation
$(D)$ $R-CH_2COOH \xrightarrow{Br_2/Red P} R-CH(Br)COOH$	$(4)$ Cannizzaro's reaction
$(E)$ $CH_3-CN \xrightarrow{SnCl_2/HCl, H_2O/H^+} CH_3-CHO$	$(5)$ Rosenmund's reduction
$(F)$ $2CH_3CHO \xrightarrow{NaOH} CH_3-CH=CH-CHO$	$(6)$ Stephen's reaction

Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$:
Assertion $A$: Acetal/Ketal is stable in basic medium.
Reason $R$: The high leaving tendency of alkoxide ion gives the stability to acetal/ketal in basic medium.
In the light of the above statements,choose the correct answer from the options given below:

Ketone reacts with $NH_2OH$ to give oxime. The reaction is as follows:
$R_2C=O + H_2N-OH \rightarrow R_2C=N-OH + H_2O$
The total number of organic products (ketoxime) formed when the simplest ketone and its next higher homologue react with $NH_2OH$,is: